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Report: Bucks, Jrue Holiday agree to four-year, max contract extension

The Bucks will pay the guard up to $160 million over four seasons.

Jrue Holiday of the Milwaukee Bucks smiles during the game against the Los Angeles Lakers on March 31, 2021 at STAPLES Center in Los Angeles, California. Photo by Adam Pantozzi/NBAE via Getty Images

The Milwaukee Bucks and PG Jrue Holiday have agreed to terms on a four-year max contract extension worth up to $160 million, per Shams Charania of The Athletic. Holiday could have become an unrestricted free agent after this season. He was acquired in a trade with the New Orleans Pelicans prior to the 2020-21 season. Holiday gets paid $26 million this season and had a player option for $27 million in 2021-22. The Bucks now have Giannis Antetokounmpo, Khris Middleton and Holiday all signed to long-term deals.

Holiday is averaging 17 points, 5.4 assists and 4.6 rebounds with 1.8 steals per game in his first season with the Bucks. Holiday was acquired in a four-team deal over the offseason with the Pels, Denver Nuggets and OKC Thunder, which also involved Steven Adams, Eric Bledsoe, George Hill and RJ Hampton.

The Bucks sit in third place in the Eastern Conference at 32-17, just 2.0 games back of the Philadelphia 76ers and Brooklyn Nets. Milwaukee has regressed a bit this season after dominating the East the past two seasons. The Bucks have had stretches where we’ve seen that dominant play, but the defense hasn’t been up to par despite getting Holiday, a strong perimeter defender.